1.

A solid AB has the NaCl structure. If the radius of the cation A^(+) is 150 pm, calculate the maximum possible value of the radius of the anion B^(-).

Answer»


Solution :For the NACL type structure, `(R^(+))/(r^(-))= 0.414 -0.732`
`:. r^(+) = 150` PM and for MAXIMUM value of `r^(-), (r^(+))/(r^(-)) = 0.414`
`:. (150)/(r^(-))= 0.414` or `r^(-) =(150)/(0.414) = 362.3` pm


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