1.

A solid compound XY has NaCl structure . If the radius of the cation is 100 pm , the radius of the anion will be ……..

Answer»

`((100)/(0.414))`
`((0.732)/(100))`
`100 xx 0.414`
`((0.414)/(100))`

Solution :`((100)/(0.414))`
For an FCC structure `(r_(X))/(r_(Y)) = 0.414` , gives that `r_(X) = 100` PM `r_(Y) = (100 "pm")/(0.414)`


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