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A solid cube of side a and density `rho_(0)` floats on the surface of a liquid of density `rho`. If the cube is slightly pushed downward, then it oscillates simple harmonically with a period ofA. `2pisqrt((rho_(0))/(rho)(a)/(g))`B. `2pi sqrt((rho)/(rho_(0))(a)/(g))`C. `2pi sqrt ((a)/((1 - (rho)/(rho_(0)))g`D. `2pi sqrt ((a)/((1 + (rho)/(rho_(0)))g` |
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Answer» Correct Answer - A `T = 2pi sqrt((m)/(k))` Here `m = (rho_(0))(a^(3))` and `K = rho_(l) A g = rhoa^(2)g` `:. T = 2pi sqrt ((rho_(0)a)/(rhog))` . |
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