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A solid cylindrical conductor of radius R carries a current along its length.The current density J_(1) however, is not unifrom over the cross section of the conductor but is a function of the radius according to J=br, where b is a constant.the magnetic field B at r_(1) lt R is (mu_(0)b r_(1)^(2))/N.Then find value of N

Answer»


Solution :`B_(1)=(mu_(0)i_(1))/(2pir_(1))`
`B_(1)=(mu_(0)br_(1)^(2))/3 ,:'i_(1)=underset(0)OVERSET(f_(1))intdi==underset(0)overset(f_(1))int(dr)(2pir dr)=(2pibr_(1)^(3))/3`


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