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A solid disc first rolls without slipping and then slides without rolling down the same inclined plane. The velocities in two cases at the bottom are in the ratio of |
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Answer» `1:2` `(1)/(2)mv_(1)^(2)+(1)/(2)xx(1)/(2)MR^(2)omega^(2)=mgh` `(1)/(2)mv_(1)^(2)+(1)/(4)mv_(1)^(2)=mgh` `(3)/(4)mv_(1)^(2)=mghimpliesv_(1)=sqrt((4gh)/(3))` When the disc slides then `(1)/(2)mv_(2)^(2)=mghimpliesv_(2)=sqrt(2gh)` `therefore (v_(1))/(v_(2))=(sqrt((4gh)/(3)))/(sqrt(2gh))=sqrt((4)/(6))implies(v_(1))/(v_(2))=2:sqrt(6)` |
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