A solid disk rotates in the horizontal plane at an angular velocity of 0.067 "rad"//s with respect to an axis perpendicular to the disk at its center. The moment of inertia of the disk is 0.10 kg.m^(2). From above, sand is dropped straight down onto this rotating disk, so that a thin uniform ring of sand is formed at a distance of 0.40 m from the axis. The sand in the ring has a mass of 0.50 kg. After all the sand is in place, what is the angular velocity of the disk?

A solid disk rotates in the horizontal plane at an angular velocity of

1.	A solid disk rotates in the horizontal plane at an angular velocity of 0.067 "rad"//s with respect to an axis perpendicular to the disk at its center. The moment of inertia of the disk is 0.10 kg.m^(2). From above, sand is dropped straight down onto this rotating disk, so that a thin uniform ring of sand is formed at a distance of 0.40 m from the axis. The sand in the ring has a mass of 0.50 kg. After all the sand is in place, what is the angular velocity of the disk?
Answer» `0.067 "RAD"//s` `0.046 "rad"//s` `0.059 "rad"//s` `0.037 "rad"//s` ANSWER :D

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