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A solid element burns in oxygen without any change in volume (of gas) under similar conditions of temperature and pressure. If the vapour density of pure gaseous product is 32, what is the equivalent mass of the element? |
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Answer» SOLUTION :One vol. of oxide contains 1 VOLT. Of `O_(2)`. One MOLE of oxide contains one mole of `O_(2)`. Mol. Mass of oxide `=A=32=2V.D.=64` 32 PARTS of element combine with 32 parts of oxygen. So, equivalent mass of element`=(32)/(32)xx8=8` |
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