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InterviewSolution
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A solid of density 5,000 kg/m³ weighs 0.5kg in air.It is completely immersed in a liquid of density 800 kg/m³. calculate the apparent weight of the solid in the liquid |
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Answer» Density ρ = 5000 KG/m 3 WEIGHT = 0.5 kg f in airmass M = 0.5 kg Volume V = M / ρ = 0.5 / 5000 = 10 −4 m 3 mass of water displaced = V ∗ density of water = 10 −4 ∗1000 = 0.1 kg Apparent weight = wt in AIR - wt of water displaced = 0.5 kg f - 0.1 kg f = 0.4 kg f |
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