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A solid rectangular piece of Iron measure 6m by 6m by 2m an find the weightof this piece if 1cm3 of Ironweighs 8gm |
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Answer» :LENGTH of cuboidal IRON piece = 6 mBreadth of the iron piece = 6 mHeight of the iron piece = 2 mWeight of 1 cm³ iron = 8 g★ To Find:The total weight of this iron piece.★ AnalysisIn this question, we first have to find the volume of the cuboid and them MULTIPLY the volume with the weight of 1 cm³ of the cuboid.★ Formulae to be used:→ → ★ Solution:Length = 6 mBreadth = 6 mHeight = 2 mVolume of any cuboid = lbhVolume of given cuboid = 6 x 6 x 2= 6 x 12= 54 m³1 m³ = 1000000 cm³So,54 m³ = 54 x 1000000 cm³= 54000000 cm³Weight of 1 cm³ iron = 8 gSo, weight of 54000000 cm³ iron= 54000000 x 8= 432000000 g= 432000 kgHence the required answer is 432000 kg [432000000 g]. |
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