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A solid sphere and a disc. Of same diameter and mass roll down from rest on a frictionless inclined plane. The ratio of their acceleration is : |
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Answer» Solution :`a=(gsintheta)/(1+(I)/(mr^(2)))` for sphere `I=(2)/(5)mr^(2) THEREFORE a_(s)=(5)/(7)gsintheta` for disc `I=(1)/(2)mr^(2) therefore a_(d)=(2)/(3)gsintheta` `therefore (a_(s))/(a_(d))=(5)/(7)xx(3)/(2)=(15)/(14)` |
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