InterviewSolution
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InterviewSolution
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A solid sphere cools at the rate of `2.8^(@)C` per minute, when its temperature is `127^(@)C`. Find the rate at which another solid copper sphere of twice the radius looses its temperature at `127^(@)C`, in both the cases, the room temperature is maintained at `27^(@)C` isA. `9.72^(@)C//`minB. `11.2^(@)C`/minC. `3.6^(@)C`/minD. `1.4^(@)C`/min |
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Answer» Correct Answer - B `(R_(2))/(R_(1))=(A_(2))/(A_(1))((T_(2)^(4)-T_(0)^(4)))/((T_(1)^(4)-T_(0)^(4)))=(4r_(1)^(2))/(r_(1)^(2))=4` `R_(2)=4R_(1)` `=4xx2.8` `=11.2` c/min. |
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