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A solid sphere of mass 1 kg rolls on a table with linear speed 2 m/s. Find its total kinetic energy. |
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Answer» Solution :DATA : M = 1 kg, v = 2 m/s The total kinetic energy of a rolling body, ` E = 1/2 Mv^(2) (1 + K^(2)/R^(2))` For a solid sphere, `k^(2) = 2/5 R^(2)` ` :. E = 1/2 Mv^(2)(1 + (2/5 R^(2))/R^(2)) = 1/2 Mv^(2) (1 + 2/5)` ` = 1/2 xx 7/5 Mv^(2) = 7/10 Mv^(2)` ` = 7/10 xx 1 xx 2^(2)` ` = (7 xx 4 )/10 = 2. 8 ` J |
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