Saved Bookmarks
| 1. |
A solid sphere of mass 10 kg is placed over two smooth inclined placed as shown in figure. The normal reactions at 2 is (g = 10 m//s^(2)) |
|
Answer» 50 `N_(1) sin 30^(@) = N_(2) sin 60^(@)` `N_(1) cos 30^(@) + N_(2) cos 60^(@) = MG` Solving above equation `N_(2) = (mg)/(2) = (10 xx 10)/(2) = 50` |
|