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A solid sphere of mass M and radius R spins about an axis passing through its centre making 600 r.p.m. What is its kinetic energy of rotation?

Answer»

`(2)/(5)PIM^(2)R^(2)`
`80pi^(2)MR^(2)`
`80piR`
`(2)/(5)pi^(2)MR`

Solution :`omega=2pin=2pixx(600)/(60)=20pi`
`therefore"Rotational K.E. of the sphere "=(1)/(2)IOMEGA^(2)`
`=(1)/(2).(2)/(5)MR^(2).(20pi)^(2)`
`=(1)/(5)MR^(2)xx400pi^(2)`
`=80pi^(2)MR^(2)`


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