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A solid sphere of masss 0.50 kg si kept on a horizontal surface. The coeffici8ent of static friction between the surfaces in contact is 2/7. What maximum force can be applied at the highest point in the horizontal direction so that the sphere does not slip on the surface? |
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Answer» Correct Answer - C If we take moment about the center than `FxxR=Ialpha+fxxR` `rarr F=2/5mRalpha+mumg`…….1 `Again F=ma_c-m mg`…….. 2 `-[because a_c=ralpha]` `rarr a=((F+mumg))/m` Putting the value of `a_c` in equation 1 we get `=(2/5)(F+mug)/m+mu mg` `rarr F=2/5F+2/5+2/5xx2/7xx0.5xx10+2.7xx0.5xx10` `rarr (3F)/5=4/7+10/7=2` `rarr F=((5x2))/3=10/3=3.3N` |
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