

InterviewSolution
Saved Bookmarks
1. |
A solid sphere of uniform density and radius `R` applies a gravitational force of attraction equal to `F_(1)` on a particle placed at `P`, distance `2R` from the centre `O` of the sphere. A spherical cavity of radius `R//2` is now made in the sphere as shown in figure. The particle with cavity now applies a gravitational force `F_(2)` on same particle placed at `P`. The radio `F_(2)//F_(1)` will be A. `9/7`B. `7/9`C. `1/2`D. `4/3` |
Answer» Correct Answer - A |
|