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A solid sphere rolls without sliding with constant velocity. What fraction of total K.E of sphere is rotational K.E. ?

Answer»

`1//5`
`2//5`
`2//3`
`2//7`

Solution :T.E. = LINEAR K.E. + ROTATIONAL K.E. `=(1)/(2)mv^(2)+(1)/(2)Iomega^(2)`
IMPLIES T.E. = `(1)/(2)mv^(2)+(1)/(5)mv^(2)=(7)/(10)mv^(2)`
implies T.E. `=(1)/(2)mv^(2)+(1)/(5)mv^(2)=(7)/(10)mv^(2)`
`therefore (E_("Rotational"))/(E_("TOTAL"))=((1)/(5)mv^(2))/((7)/(10)mv^(2))=(2)/(7)`


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