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A solid uniform disc of mass `m` rols without slipping down a fixed inclined plank with an acceleration a. The frictional force on the disc due to surface of the plane isA. `(1)/(4)ma`B. `(3)/(2)ma`C. `ma`D. `(1)/(2)ma` |
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Answer» `a=(gsintheta)/(1+I//mR^(2))=(gsintheta)/(1+(1//2))` `=(2gsintheta)/(3)` `thereforegsintheta=(3)/(2)a` Now, `f=(mgsintheta)/(1+mR^(2)//I)=(m(3//2a))/(1+2)` `=(1)/(2)ma` |
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