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A solid uniform sphere resting on a rough horizontal plane is given a horizontal impulse directed through its centre so that it starts sliding with an initial velocity v_(0). When it finally starts rolling without slipping the speed of its centre is |
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Answer» `2/7v_(0)`  Let M and R be mass and RADIUS of the solid SPHERE respectively. Applying law of conservation of angular momentum about the point of contact, we get `Mv_(0)R=MvR+2/5MR^(2)omega(because` For solid sphere, `I=2/5MR^(2))` `=MvR+2/5MR^(2)(v/R)=7/5MvR(becausev=Romega)` `v_(0)=7/5v` or `v=5/7v_(0)` |
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