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A solution containing 0.10 g of non-volatile solute X (molar mass : 100) in 200 g of benzene depresses the freezing point of benzene by 0.25^(@)C while 0.50 g of another non-volatile solute Y in 100 g of benzene also depresses the freezing point of benzene by 0.25^(@)C. What is the molecular mass of Y ? |
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Answer» 50 `or M'_(2)=(w'_(2))/(w'_(1))xx(w_(1))/(w_(2))xxM_(2)=(0.50)/(100)xx(200)/(1.10)XX100` = 1000 |
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