1.

A solution containing 0.319 gm of complex CrCl_(3).6H_(2)O was passed through cation exchanger and the solution given out was neturalised by 28.5 ml of 0.125 M NaOH. The correct formula of the complex will be : [Molecular weight of complex = 266.5]

Answer»

`[CrCl(H_(2)O)_(5)]Cl_(2).H_(2)O`
`[CrCl(H_(2)O)_(6)]Cl_(3)`
`[CrCl_(2)(H_(2)O)_(4)]Cl.2H_(2)O`
all are correct

Solution :`n_(CrCl_(3).6H_(2)O)=0.319/266.5`
m MOL of NaOH=3.5625
`3CL^(-)harr3OH^(-)rArr1.97xx3=3.5625`
`RARR [Cr(H_(2)O)6]Cl_(3)`


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