1.

A solution containing 0.85 g of ZnCI_(2) in 125.0g of water freezes at -0.23^(@)C. The apparent degree of dissociation of the salt is: (k_(f) for water = 1.86 K kg mol^(-1), atomic mass, Zn = 65.3 and CI = 35.5)

Answer»

`0.875 M`
`1.00M`
`1.75M`
`0.975M`

Solution :`M_("resultant") = (M_(1)V_(1)+M_(2)V_(2))/(V_("TOTAL"))`
`= (0.5 xx 750 + 2XX 250)/(1000)`
`= (375 +500)/(1000) = 0.875M`


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