1.

A solution containing 1.8 g of a compound (empirical formula CH_(2)O) in 40 g of water is observed to freeze at -0.465^(@)C. The molecular formula of the compound is (K_(f) of water = 1.86 kg k "mol"^(-1))

Answer»

`C_(2)H_(4)O_(2)`
`C_(3)H_(6)`
`C_(4)H_(8)O_(4)`
`C_(6)H_(12)O_(6)`

Solution :`M_(2)=(1000K_(f)w_(2))/(w_(1)xxDeltaT_(f))=(1000xx1.86xx1.8)/(40xx0.465)=180`
`"E.F. mass "CH_(2)O=30 THEREFORE n=(180)/(30)=6`
`therefore"Molecular formula "=6xxCH_(2)O=C_(6)H_(12)O_(6)`


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