1.

A solution containing 10.2 g glycerine per litre of a solution is found to be isotomic with 2.0% solution of glucose (Molar mass 180). Calculate the molecular mass of glycerine.

Answer»


Solution :`"Molar conc. of glycerine "=10.2//M" (M = MOL. MASS)"`
`"Molar conc. of glucose "=(2)/(180)XX(1)/(100)xx1000="0.111 mol L"^(-1)""therefore""(10.2)/(M_(2))=0.111"or"M_(2)=91.9"G mol"^(-1)`.


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