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A solution containing 10 g/litre of surcose has an osmotic pressure of 0.66 atm at 273 K. Calculate the value of the constant R. |
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Answer» Solution :Here, we are GIVEN that `"C = 10 G/litre "=(10)/(342)" moles/litre"` `""(because "Molar mass of sucrose "C_(12)H_(22)O_(11)="342 g MOL"^(-1))` `PI=0.66 atm,"T = 273 K"` Using the equation, `pi=CRT`, we have `R=(pi)/(CT)=("0.66 atm")/((10)/(342)" mol L"^(-1)xx"273 K")=(0.66xx342)/(10xx273)"L atm K"^(-1)"mol"^(-1)="0.0827 L atm K"^(-1)"mol"^(-1)`. |
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