1.

A solution containing 18 g of anon-volitile solute in 200 g of waer freezes at 272.07 K. Calculate the molecular mass of the solute. (Given K_(f)=1.86 K/m)

Answer»


Solution :`W_(B)=18g, W_(A)=0.2Kg, K_(f)=1.86," K kg MOL"^(-1), T_(f)=273 K, T_(f)=272.07 K`
`DeltaT_(f)=T_(f)^(@)-T_(f)=273-272.07=0.93 K, M_(B)=?`
`M_(B)=(K_(f)xxW_(B))/(DeltaT_(f)xxW_(A))=((1.86" K kg mol"^(-1))XX(18g))/((0.93K)xx(0.2 Kg))=180" g mol"^(-1).`


Discussion

No Comment Found

Related InterviewSolutions