1.

A solution containing 2.675 g of CoCl_(3). 6 NH_(3) (molar mass = 267.5 g "mol"^(-1)) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of AgNO_(3) to give 4.78 g of AgCl (molar mass = 143.5 g "mol"^(-1)). The formula of the complex is (At. Mass of Ag = 108 u)

Answer»

`[Co(NH_(3))_(6)]Cl_(3)`
`[CoCl_(2)(NH_(3))_(4)]CL`
`[COCL(NH_(3))_(3)]Cl_(3)`
`[CoCl(NH_(3))_(5)]Cl_(2)`

ANSWER :A


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