A solution containing 2.675 g of CoCl_(3).6NH_(3) (molar mass = 267.5 g "mol"^(-1)) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of AgNO_(3) to give 4.78 g of AgCl (molar mass = 143.5 g "mol"^(-1)). The formula of the complexis : (At. mass of Ag = 108u)

A solution containing 2.675 g of CoCl_(3).6NH_(3) (molar mass = 267.5

1.	A solution containing 2.675 g of CoCl_(3).6NH_(3) (molar mass = 267.5 g "mol"^(-1)) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of AgNO_(3) to give 4.78 g of AgCl (molar mass = 143.5 g "mol"^(-1)). The formula of the complexis : (At. mass of Ag = 108u)
Answer» `[CoCl_(3)(NH_(3))_(3)]` `[CoCl(NH_(3))_(5)]Cl_(2)` `[Co(NH_(3))_(6)]Cl_(3)` `[CoCl_(2)(NH_(3))_(4)]Cl`. Solution :Moles of complex `=(2.675)/(267.5)=0.01` Moles of AgCl precipitated `=(4.78)/(143.5)=0.03` `therefore Cl^(-)` IONS produced = 0.03 moles. It shows that 3 moles of `Cl^(-)` ions are produced per mole of complex. `therefore` Possible structure of complex is `[Co(NH_(3))_(6)]Cl_(3)`. `UNDERSET(0.01"mol")underset(1"mol")([Co(NH_(3))_(6)]Cl_(3)) to [Co(NH_(3))_(6)]^(3+) +underset(0.03"mol")underset(3"mol")(3Cl^(-))`