1.

A solution containing 25.6 g of sulphur, dissolved in 1000 g of naphthalene whose melting point is 80.1^(@)C gave a freezing point lowering of 0.680^(@)C. Calculate the formula of sulphur (K_(f) for napthalene =6.8 K m^(-1))

Answer»


Solution :`W_(B)=25.6g, W_(A)=1 kg, DeltaT_(f)=0.68K, K_(f)=6.8" k kg mol"^(-1)`
`M_(B)=(K_(f)xxW_(B))/(DeltaT_(f)xxW_(A))=((6.8" K kg mol"^(-1))xx(25.6 g))/((0.68K)xx(1kg))=256" g mol"^(-1)`
`"Atomicity of sulphur"=((256" g mol"^(-1)))/((32" g mol"^(-1)))=8`
`"THEREFORE, molecular fomula of sulphur"=S_(8)`.


Discussion

No Comment Found

Related InterviewSolutions