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A solution containing 6 g of benzoic acid, C_(6)H_(5)COOH in 50 g of diethy 1 ether, C_(2)H_(5)OC_(2)H_(5), has a vapour pressure of 410 mm Hg at 293 K. Calculate the molar mass of the benzoic acid. Vapour pressure of diethy1 eth at 293 K is 442 mm Hg. |
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Answer» `M_(A)(C_(2)H_(5)-O-C_(2)H_(5))=74" g mol"^(-1)` According to Raoult's Law(solution is non-ideal), `(P_(A)^(@)-P_(S))/P_(S)=n_(B)/n_(A)=W_(B)/M_(B)xxM_(A)/W_(A)` `((442-410)mm)/(410 mm)=((6g))/((M_(B)))XX((74" g mol"^(-1)))/((50 g))` `M_(B)=((6g)xx(74" g mol"^(-1)))/((50g))xx((410 mm))/((32mm))=113.8" g mol"^(-1)`. |
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