1.

A solution containing 62.5 g of non-volatile solute per 1000 g of water hass a greezing point 1.06^(@)C less than tha of water. Calculate the molecular mass of the solute. (K_(f)=1.86 K kg mol^(-1))

Answer»


SOLUTION :`W_(B)=62.5g, W_(A)=1 KG, DeltaT_(f) =1.06^(@)C=1.06 K`
`K_(f)=1.86" K kg mol"^(-1), M_(B)=?`
`M_(B)=(K_(f)xxW_(B))/(DeltaT_(f)xxW_(A))=((1.86" K kg mol"^(-1))xx(62.5 g))/((1.06 K)xx1Kg)=109.67" g mol"^(-1)`


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