Saved Bookmarks
| 1. |
A solution contains 1 mCi of L-phenylalanine C^(14) labelled in 2.0 mL solution. The specific activity of labelled sample is given as 150 mCi "mmol"^(-1). Calculate (a) The concentration of the sample in the solution in "mol" L^(-1) (b). The activity of solution in terms of counting per minute per mL at counting of 80% |
|
Answer» SOLUTION :a. 1 mmol ` = 150 mCi` `1 mCi = (1)/(150)` mmol `= (1)/(150 xx 2) = 3.33 xx 10^(-2) M` b. `1 Ci = 3.7 xx 10^(10) dps` `= 3.7 xx 10^(10) xx 60 dpm` `= 3.7 xx 10^(10) xx 60 xx (80)/(100)` counts `"min"^(-1)` `= (177.6 xx 10^(10))/(2 ML) = 88.8 xx 10^(10)` counts `"min"^(-1) mL^(-1)` ` mCi = 88.8 xx 10^(7)` count `"min"^(-1) mL^(-1)` |
|