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A solution contains 90 g of H_(2)O, 6.4 g of methanol and 18.4 g of glycerol. What is the mole fraction of glycerol ? ("Glycerol "=CH_(2)OH-CHOH-CH_(2)OH)

Answer»


SOLUTION :`"MOLE FRACTION of GLYCEROL "=(18.4//92)/(18.4//92+90//18+6.4//32)=(0.2)/(0.2+5+0.2)=(0.2)/(5.4)=0.037`


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