1.

A solution contains Fe^(2+),Fe^(3+) and I^(-) ions. This Fe^(3+)//Fe^(2+) is +0.77 V and E^(@) for I_(2)//2I^(-) is 0.536 V. the favourable redox reaction is

Answer»

`I_(2)` will be reduced to `I^(-)`
There will be no redox reaction
`I^(-)` will be oxidized to `I_(2)`
`FE^(2+)` will be oxidised to `Fe^(3+)`

SOLUTION :The reaction will take place for which `E_(cell)^(@)` is positive.
(a) `I_(2)+2e^(-)to2I^(-),E_(red)^(@)=0.536V`
`Fe^(2+)toFe^(3+)+e^(-),E_(o x )^(@)=-0.770V`
`thereforeE_(cell)^(@)` will be -ve.
(b) Redox reaction will occur.
(c) `2I^(-)toI_(2)+2e^(-),E_(o x)^(@)=0.536V`
`underline(""Fe^(3+)+e^(-)toFe^(2+),E_(red)^(@)=+0.770V"")`
`2FE^(3+)+2I^(-)to2Fe^(2+)+I_(2),E_(cell)^(@)=+0.164V`
Thus, `E_(cell)^(@)` is +ve. hence, this reaction will occur.
(d). also will not occur.


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