A solution contians a mixutre of Na_(2) CO_(3) and NaOH. Using phenolphthalein as indicator 25ml of mixturerequired 19.5 ml of 0.995 N HCl for the end point. With methyl organge. 25 ml of solution required 25ml, of the same . HCl for the end point. Calculate grams per litre of each substance in the mixture.

A solution contians a mixutre of Na_(2) CO_(3) and NaOH. Using phenolp

1.	A solution contians a mixutre of Na_(2) CO_(3) and NaOH. Using phenolphthalein as indicator 25ml of mixturerequired 19.5 ml of 0.995 N HCl for the end point. With methyl organge. 25 ml of solution required 25ml, of the same . HCl for the end point. Calculate grams per litre of each substance in the mixture.
Answer» Solution :meq of `Na_(2) CO_(3) =2 xx `moles`Na_(2) CO_(3) = a ` meq of NaOH =`b=1xx` moles of NaOH with PHENOL PHTHALEIN `Na_(2)CO_(3) + HCl rarr NaHCO_(3) + NACL`nf = 1 `NaOH + HCl rarr NaCl + H_(2) O`nf = 1 `:. a//2+b =` meq of HCl = `9.5 xx 0.995 = 19.4 `with methyl orange `Na_(2) CO_(3) + HCl rarr NAcL +H_(2) CO_(3)`nf = 2 `NaOH + HCl rarr NaCl + H_(2) O`nf = 1 `a+b =` meq of HCl `= 25 xx .995 = 24.875` `a//2=5.475 rArr a = 10.95 .b = 13.925` wt of `Na_(2) CO_(3) //` lit `= ( 10.95)/( 25) xx 10^(-3) xx ( 106)/( 2) xx 1000 = 23.2 gm//lit ` wt ofNaOH `//` lit `= b xx 10^(-3) xx 84 // 25 xx1000 = 22.8 gm //lit `