1.

A solution has 1:4 mole ratio of pentane to hexane . The vapour pressure of pure hydrocarbons at 20^@Care 440mmHgfor pentane and 120mmHg for hexane .The mole

Answer»

0.2
0.549
0.786
0.478

Solution :`(n_(C_(5)H_(12)))/(n_(C_(6)H_(14)))=1/4`
`X_(C_(5)H_(12))=1/(1+4)=1/5`
`X_(C_(6)H_(14))=4/(1+4)=4/5`
`P_(C_(5)H_(12))^(@)=440mmHg,P_(C_(6)H_(14))^(@)=120 mm Hg`
`P_(("TOTAL"))=P_(C_(5)H_(12))^(@)xxX_(C_(5)H_(12))+P_(C_(6)H_(14))^(@)xxX_(C_(6)H_(14))`
`=440xx1//5+120xx4//5`
`=88+96=184 mm Hg`
Mole fraction `C_(5)H_(12)` in vapour phase
`X_(C_(5)H_(12))=("Partoa V.P. of "C_(5)H_(12))/("Partoa V.P. of "C_(6)H_(14))=(88mm)/(184mm)=0.478`


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