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A Solution is prepared by dissolvingcertain amountofsolute in 500 g water. The %by massof asolutionsis 2.38 . Calculate mass ofthe solute.

Answer»


Solution :Given : `W_(1)`= Massof a SOLVENT(water) = 500 g
`W_(2)` Massof a solute =?
%by MASS= % `(W//W) = 2. 38`
Let massof thesolute`=W_(2) =X g`
`:.` Massof the solution`= W_(1) + W_(2)= (500 + x) g`
Nowper centby massof solute `= ("massof solute")/("massof solution") xx 100`
`= ("mass of solute")/("mass ofsolvent+ massof solute") xx 100`
`:. 2.38= (X )/((500 + X)) xx 100`
`:. 2. 38(500 + X) =100 x`
`:. 2.38 xx 500 + 2.38 X =100 x`
`:.1190 + 2.38 X = 100 x`
`:.100 x -2.38 x= 1190`
`:. (100 -2.38) x= 1190`
`:. 97 .62 x = 1190`
`:. x = (1190)/(96.62) =12.19`


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