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A solution of 0.10 M of a weak electrolyte is found to be dissociated to the extent of 1.20% at 25^@C . Find the dissociation constant of the acid. |
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Answer» SOLUTION :GIVEN that `a=1.20%=1.20/100=1.2 TIMES 10^-2` `K_a=a^2c=(1.2 times 10^-2)^2 (0.1)` `=1.44 times 10^-4 times 10^-1=1.44 times 10^-5` |
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