1.

A solution of 0.20 g of a non-electrolyte in 2 g of water freezes at 271.14 K . If K_(f) = 1.86 K "molality"^(-1)then the molar mass of the solute is :

Answer»

207.8 g//mol
179.79 g//mol
200.8 g//mol
100.0 g//mol

Solution :`DELTA T_(F)=(1000_(f) XX W_(2))/(M_(2) W_(1))`
or `1.86=(1000 xx 1.86 xx 0.20)/(M_(2) xx 20)`
`:. M_(2) = (1000 xx 1.86 xx 0.20)/(1.86 xx 20 )=100.0`


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