1.

A solution of 7 g of a non-volatile solute in 250 g of water boils at 100.26^(@)C. Find the molecular mass of th solute K_(b) for water is 0..52 K kg mol^(-1) .

Answer»


Solution :Elevation in BOILING point, `DeltaT_(b)=100.26-100=0.26^(@)C=0.26 K`
`M_(B)=(K_(B)xxW_(B))/(DeltaT_(b)xxW_(A))=((0.52" K kg mol"^(-1))XX(7g))/((0.26 K)xx(0.250" Kg"))=56" g mol"^(-1)`


Discussion

No Comment Found