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A solution of a salt of metal was electrolysed for 15 minutes with a current of 0.15 amperes. The mass of the metal deposited at the cathode is 0.783 g. Calculate the equivalent mass of the metal. |
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Answer» Solution :`I=0.15` amperes times `t=15 times 60s=900s` mass `m=0.783g` `m=2It` `z=m/(It)` `Q=I times t=0.15 times 900 C` Amount of the metal DEPOSITED by 1 C `=0.783/135=0.0058` Electrochemical equivalent `Z=5.8 times 10^(-3)GC^(-1)`. |
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