1.

A solution of CaCl_(2) is mol/litre, then the moles of chloride ions in 500 mL will be

Answer»

0.25
0.5
0.75
1

Solution :`M=n/(V(ML)) xx 1000`
`0.5=n/500 xx 1000`
`n=0.5/2=0.25` moles of `CaCI_(2)`
`As CaCI_(2) hArr Ca^(2+) + 2 CI^(-)`


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