1.

A solution of CuSO_(4) is electroysed for 10 minutes with a current of 1.5 amperes. What is the mass of copper deposited at the cathode ? (Molar mass of Cu=63.5 g//mol)

Answer»

Solution :`I=1.5" AMPERE"`
`"Time "=10xx60s=600s`
`Q=Ixxt`
`=1.5xx600=900C`
`Cu^(2+)+2e^(-)rarrCu(s)`
2F amount of electricity DEPOSIT copper = 63.5 G
`"900 C amount of electricity deposit copper"=(63.5xx900)/(2xx96500)`
`=0.296g`


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