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A solution of CuSO_(4) is electroysed for 10 minutes with a current of 1.5 amperes. What is the mass of copper deposited at the cathode ? (Molar mass of Cu=63.5 g//mol) |
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Answer» Solution :`I=1.5" AMPERE"` `"Time "=10xx60s=600s` `Q=Ixxt` `=1.5xx600=900C` `Cu^(2+)+2e^(-)rarrCu(s)` 2F amount of electricity DEPOSIT copper = 63.5 G `"900 C amount of electricity deposit copper"=(63.5xx900)/(2xx96500)` `=0.296g` |
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