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A solution of glucose in water is labelled as 10% w/w. What would be the molality and mole fraction of each component in the solution? If the density of the solution is "1.2 g mL"^(-1). Then what shall be the molarity of the solution? |
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Answer» Solution :10 g glucose is present in 100 g solution, i.e., 90 g of water = 0.090 kg of water `"10 g of glucose "=(10)/(180)" mol = 0.0555 mol,90 g "H_(2)O=(90)/(18)="5 MOLES"` `"MOLALITY"=("0.0555 mol")/("0.090 kg")=0.617 m"` `"x (Glucose)"=(0.0555)/(5+0.555)=0.01, x(H_(2)O)=1-0.01=0.99` `"100 g solution"=(100)/(1.2)mL = "83.33 mL = 0.08333 K ,Molarity "=("0.0555 mol")/("0.08333 L")="0.67 M".` |
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