A solution of glucose in water is labelled as 10% w/w, what would be the molality and mole fraction of each component in the solution ? If the density of solution is 1.2 g mL^(-1), then what will be the molarity of the solution ?

A solution of glucose in water is labelled as 10% w/w, what would be t

1.	A solution of glucose in water is labelled as 10% w/w, what would be the molality and mole fraction of each component in the solution ? If the density of solution is 1.2 g mL^(-1), then what will be the molarity of the solution ?
Answer» SOLUTION :0 % w / w solution of glucose in water means that 10 g glucose in present in 100 g of the solution i.e., 10 g of glucose is present in (100 - 10) g = 90 g of water. Molar mass of glucose `(C_(6)H_(12)O_(6))` `= 6xx12+12xx1+6xx16` `= 180 g MOL^(-1)` Then, number of MOLES of glucose `= (10)/(180)mol` = 0.056 mol Molarity of solution `= (0.056 mol)/(0.09 KG)=0.62 m` Number of moles of water `= (90 g)/(18 g mol^(-1))=5 mol` Mole fraction of glucose `(x_(g))=(0.056)/(0.056+5)=0.011` And, mole fraction of water `X_(w)=1-x_(g)` `=1-0.011` = 0.989 If the ensity of the solution is 1.2 kg `mL^(-1)`, then the volume of the 100 g solution can be given as, `= (100 g)/(1.2 g mol^(-1))` = 83.33 mL `= 83.33xx10^(-3)L` `therefore` Molarity of the solution `= (0.056 mol)/(83.33xx10^(-3)L)` = 0.67 M.