1.

A solution of glucose (Molar mass ="180 g mol"^(-1)) in water has a boiling of 100.20^(@)C. Calculate the freezing point of the same solution. Molal constants for water K_(f) and K_(b) are "1.86 K kg mol"^(-1) and 0.512 K kg "mol"^(-1) respectively.

Answer»


SOLUTION :`m=(DeltaT_(B))/(K_(b))=(0.20)/(0.512)=0.39""DeltaT_(F)=K_(f)m=1.86xx0.39=0.73^(@)`


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