1.

A solution of glycerol (C-(3)H_(8)O_(3) , molar mass = 92 g mol^(-1) iin water was prepared by dissolving some glycero 500 g of water. This solution has a boiling point of 100.42^(@)C. What mass of glycerol was dissolved to make this solution ? K_(b) for water= 0.512 k kg mol^(-1).

Answer»


Solution :`DeltaT_(B)=(100.42^(@)C-100)^(@)C=0.42^(@)C=0.42" K",`
`M_(B)=92" G mol"^(-1),W_(A)=500 g =0.5" kg",`
`K_(b)=0.152" k kg mol"^(-1)`
`W_(B)=(M_(B)xxDeltaT_(b)xxW_(A))/(K_(b))=((92g mol^(-1))xx(0.42K)xx(0.5kg))/((0.512" k kg mol"^(-1)))=37.7 g`.


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