1.

A solution of impure KMnO_4 is prepared by dissolving 2g of it in IL of the solution. 20 ml of this solution required 24.2 ml of N/(20) sodium oxalate solution. The percentage purity of KMnO_4 sample is :

Answer»

`95.6%`
`92.2%`
`98.0%`
`84%`

Solution :`N_1V_1-=N_2V_2`
`N_1 XX 20 = (N)/(20) xx 24.2`
`N_1= (24.2)/(400) =(6.05)/(100)`
Strength `=(6.05)/(100) xx 31.6 = 1.91` g
% Purity `=(1.91)/(2.0) xx 100 = 95.5%`


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