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A solution of KMnO_(4) on reduction yields either a colourelesssolution or a brown precipitate or a green solution depending on Ph of the solution. What different stages of the reduction do these represent and how are they carried out ? |
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Answer» Solution :`KMnO_(4)` is anoxidizing agent. Its OXIDISING behaviour depends UPON pH of the solution. In acidic medium `(pH LT 7) , MnO_(4)^(-) + 8H^(+) + 5e^(-) rarr underset("(Coloureless)")(Mn^(2+)) + 4H_(2)O` In alkaline medium `( pHgt 7) , MnO_(4)^(-) + e^(-) rarr underset("(Green)")(MnO_()^(2-))("manganese")` Inneutral medium `( pH= 7 ) , MnO_(4)^(-)+ 2H_(2)O + 3E^(-) rarr underset("(Brown PPT.)")(MnO_(2)) + 4OH^(-)` |
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