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A solution of Ni(NO_(3))_(2) is electrolysed between platinum electrodes using a current of 5.0 ampere for 20 minutes. What mass of nickel will be deposited at the cathode? (At. Mass of Ni=58.7) |
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Answer» Solution :Quantity of electricity PASSED=(5A)`xx(20xx60s)=6000C` `NI^(2+)+2e^(-)toNi` Thus, `2F`, i.e., `2xx96500C` deposit Ni=1 MOLE, i.e., 58.7g `therefore6000C` will deposit `Ni=(58.7)/(2xx96500)xx6000g=1.825g`. |
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